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在windows 调试中可以正常在job中关联 子进程，并且在主进程异常退出时，子进程同时退出，子进程的创建 使用 CreateProcess方法；

！！！！！！但是 ！！！！！！！

问题：

解决办法：

BOOL CreateProcessA(  LPCSTR                lpApplicationName,  LPSTR                 lpCommandLine,  LPSECURITY_ATTRIBUTES lpProcessAttributes,  LPSECURITY_ATTRIBUTES lpThreadAttributes,  BOOL                  bInheritHandles,  DWORD                 dwCreationFlags,  LPVOID                lpEnvironment,  LPCSTR                lpCurrentDirectory,  LPSTARTUPINFOA        lpStartupInfo,  LPPROCESS_INFORMATION lpProcessInformation);

如下：

if (CreateProcess(_T(“子进程”), _T(""), NULL, NULL, FALSE, CREATE_BREAKAWAY_FROM_JOB, NULL, NULL, &info, &processInfo))

原因：

A process can be associated only with a single job. A process inherits limits from the job it is associated with and adds its accounting information to the job. If a process is associated with a job, all processes it creates are associated with that job by default. To create a process that is not part of the same job, call the CreateProcess function with the CREATE_BREAKAWAY_FROM_JOB flag.

MSDN :

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